Definition
An instance S of the parameterized data type interval_set<I> is a collection of items (is_item). Every item in S contains a closed interval of the double numbers as key and an information from data type I, called the information type of S. The number of items in S is called the size of S. An interval set of size zero is said to be empty. We use <x,y,i> to denote the item with interval [x,y] and information i; x (y) is called the left (right) boundary of the item. For each interval [x,y] there is at most one item <x,y,i> in S.
Creation
interval_set<I> | S; | creates an instance S of type interval_set<I> and initializes S to the empty set. |
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Operations
double | S.left(is_item it) | returns the left boundary of item it.
Precondition: it is an item in S. |
double | S.right(is_item it) | returns the right boundary of item it.
Precondition: it is an item in S. |
I | S.inf(is_item it) | returns the information of item it.
Precondition: it is an item in S. |
is_item | S.insert(double x, double y, I i) | |
associates the information i with interval [x,y]. If there is an item <x,y,j> in S then j is replaced by i, else a new item <x,y,i> is added to S. In both cases the item is returned. | ||
is_item | S.lookup(double x, double y) | |
returns the item with interval [x,y] (nil if no such item exists in S). | ||
list<is_item> | S.intersection(double a, double b) | |
returns all items <x,y,i> in S with [x,y] <intersection> [a,b] != emptyset. | ||
void | S.del(double x, double y) | deletes the item with interval [x,y] from S. |
void | S.del_item(is_item it) | removes item it from S.
Precondition: it is an item in S. |
void | S.change_inf(is_item it, I i) | |
makes i the information of item it.
Precondition: it is an item in S. |
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void | S.clear() | makes S the empty interval_set. |
bool | S.empty() | returns true iff S is empty. |
int | S.size() | returns the size of S. |
Implementation
Interval sets are implemented by two-dimensional range trees [79,51]. Operations insert, lookup, del_item and del take time O(log^2 n), intersection takes time O(k + log^2 n), where k is the size of the returned list. Operations left, right, inf, empty, and size take time O(1), and clear O(nlog n). Here n is always the current size of the interval set. The space requirement is O(nlog n).